# [CC150v4] 20.8 Full Text Search (Suffix Tree)

### Question

Given a string s and an array of smaller strings T, design a method to search s for each small string in T.

### Solution

This is a very classic question of string search, favored by Google and Facebook.

The solution is suffix tree (to be distinguished from trie, or prefix tree, which searched word by its prefix). Suffix tree is good for search a proportion of a long string. For example, using “bibs” to build a suffix tree like this:

The building of suffix tree and searching is not a very lengthy code. It’s posted below and it’s not written by me.

### Code

Main method:

``````public static void main(String[] args) {
String testString = "mississippi";
String[] stringList = { "is", "sip", "hi", "sis" };
SuffixTree tree = new SuffixTree(testString);
for (String s : stringList) {
ArrayList<Integer> list = tree.getIndexes(s);
if (list != null) {
System.out.println(s + ": " + list.toString());
} else {
System.out.println(s + ": does not exist.");
}
}
}
``````

SuffixTree.java

``````public class SuffixTree {
SuffixTreeNode root = new SuffixTreeNode();

public SuffixTree(String s) {
// create a suffix tree with input string s
for (int i = 0; i < s.length(); i++) {
String suffix = s.substring(i);
root.insertString(suffix, i);
}
}

public ArrayList<Integer> getIndexes(String s) {
return root.getIndexes(s);
}
}
``````

SuffixTreeNode.java

``````public class SuffixTreeNode {

char value;
HashMap<Character, SuffixTreeNode> children;
ArrayList<Integer> indexes = new ArrayList<Integer>();

public SuffixTreeNode() {
children = new HashMap<Character, SuffixTreeNode>();
}

public void insertString(String s, int index) {
if (s != null && s.length() > 0) {
value = s.charAt(0);
SuffixTreeNode child = null;
if (children.containsKey(value)) {
child = children.get(value);
} else {
child = new SuffixTreeNode();
children.put(value, child);
}
String remainder = s.substring(1);
child.insertString(remainder, index);
}
}

public ArrayList<Integer> getIndexes(String s) {
if (s == null || s.length() == 0) {
return indexes;
} else {
char first = s.charAt(0);
if (children.containsKey(first)) {
String remainder = s.substring(1);
return children.get(first).getIndexes(remainder);
}
}
return null;
}
}
``````